I just came up with a way to calculate the complexity of your household based on the number of children in it.

First, take the average of all of your children's IndividualComplexityValues (see below) in years of all of the children in your care, including those that are only there part time. This will form the base. (Note if the result comes out to a value less than or equal to 1, then add 1 to it, then multiply it by itself, and use that as the base.

Now, raise that number by powers based on the IndividualComplexityValues of all of the children in the household.

IndividualComplexityValues are calculated like this: For children aged 1 to 10: it's just their age. For very tiny children/babies aged less than one: it's 13 minus the number of months old they are. For children age 11 and above, it's one tenth their age.

For example, let's suppose you have three children in your household of the following ages:

11 months, 4, 16. Then the average would be:

(0.9166, + 4, + 1.6) / 3 is approx = 2.1722.

So, to figure the Children Complexity Value we would perform:

2.1722 ^ ( ( 13 - 11 ) ^ ( 4 ^ 1.6 ) ) .

So that would mean that your over-all household complexity is just about... 5.212 times 10^196. And of course, in my case, the Complexity calculation comes out to something far beyond perl's ability to calculate so it just answers with "inf" for infiity. Seems pretty accurate to me.

--

Furry cows moo and decompress.

## Thursday, September 17, 2009

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